Question

A pure silver coin weighs 8.062 grams. Determine the volume (in L) if the density of silver is

1.049 x 10^4 kg/m^3.
(1 L = 1.0 x 10^-3 m^3)

Answer 1

`V=7.68* 10^(-4)\ L`

Step-by-step explanation:

It is given that,

Weight of silver coin, m = 8.062 grams

The density of silver,
`d=1.049 * 10^4\ kg/m^3`

We need to find the volume of the coin.

Density = mass per unit volume

`d=(m)/(V)\\\\\implies \ V=(m)/(d)\\\\V=(8.062* 10^(-3)\ kg)/(1.049* 10^4\ kg/m^3)\\\\V=7.68* 10^(-7)\ m^3`

Since,
`1\ L=10^(-3)\ m^3`

⇒
`1\ m^3=10^3\ L\\\\7.68* 10^(-7)\ m^3=7.68* 10^(-7)* 10^3\ L\\\\V=7.68* 10^(-4)\ L`

Hence, the volume is
`7.68* 10^(-4)\ L`.