Question

(2-5√8)(4-6√3)
I need help​

Answer 1

see explanation

Explanation:

Using the rule of radicals

`√(a)` ×
`√(b)` ⇔
`√(ab)`

Given

(2 - 5
`√(8)` )(4 - 6
`√(3)` )

Each term in the second factor is multiplied by each term in the first factor, that is

2(4 - 6
`√(3)` ) - 5
`√(8)`(4 - 6
`√(3)` ) ← distribute both parenthesis

= 8 - 12
`√(3)` - 20
`√(8)` + 30
`√(24)` → *

Simplify
`√(8)` and
`√(24)`

`√(8)` =
`√(4(2))` =
`√(4)` ×
`√(2)` = 2
`√(2)`

`√(24)` =
`√(4(6))` =
`√(4)` ×
`√(6)` = 2
`√(6)`

Back to *

= 8 - 12
`√(3)` - 20(2
`√(2)` ) + 30(2
`√(6)` )

= 8 - 12
`√(3)` - 40
`√(2)` + 60
`√(6)`