Question

1. A trip was planned by a small family. Their car has a cruising speed of 30 m/s with all members in the car. From rest, the car traveled 130.5 meters to reach the car's cruising speed. What was the car's acceleration?

Answer 1

`\boxed{\sf Acceleration \ of \ the \ car \ (a) = 2.4 \ m/s^2}`

Given:

Initial speed (u) = 0 m/s (Starts from rest)

Final speed (v) = 30 m/s

Distance travelled (s) = 130.5 m

To Find:

Acceleration of the car (a)

Step-by-step explanation:

From equation of motion we have:

`\boxed{ \bold{ {v}^(2) = {u}^(2) + 2as}}`

By substituting value of v, u & s in the equation we get:

`\sf \implies {25}^(2) = {0}^(2) + 2a * 130.5 \\ \\ \sf \implies {25}^(2) = 2a * 130.5 \\ \\ \sf \implies {25}^(2) = 261a \\ \\ \sf \implies 625 = 261a \\ \\ \sf \implies 261a = 625 \\ \\ \sf \implies a = (625)/(261) \\ \\ \sf \implies a = 2.4 \: m {s}^( - 2)`