Question

27^(x) = 9^(x−4)

x = 8
x = 4
x = −4
x = −8

Answer 1

Explanation:

Change 27 to 3^3, and change 9 to 3^2 to get:

`{ ({3}^(3) )}^(x) = { ({3}^(2)) }^(x - 4)`

Multiply the exponents according to exponential rules:

`{3}^((3x)) = {3}^((2x - 8))`

Same bases, so set exponents equal to each other:

`3x = 2x - 8`

Subtract 2x on both sides to get:

`x = - 8`