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NEED HELP PLEASEE An object is launched from a platform. The equation for the object's height h at time t seconds after launch is h = -41^2+ 16t+ 48. When does the object strike the ground (How many seconds
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NEED HELP PLEASEE

An object is launched from a platform. The equation for the object's height h at time t seconds after launch is h = -41^2+ 16t+ 48. When does the object strike the ground (How many seconds after launch)?

User AlexeySRG
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1 Answer

3 votes

Answer:

Simplify−412+16t+48.h=16t−1633

Step-by-step explanation:

User Yariv Adam
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