Question

How long will it take a car to go from a complete stop to 44 m/s if they are

accelerating at 5 m/s^2?

Answer 1

`\boxed{\sf Time \ taken \ (t) = 8.8 \ s}`

Given:

Initial velocity (u) = 0 m/s

Final velocity (v) = 44 m/s

Acceleration (a) = 5 m/s²

To Find:

Time taken (t)

Step-by-step explanation:

From equation of motion we have:

`\boxed{ \bold{v = u + at}}`

By substituting value of u, v & a in the equation we get:

`\sf \implies 44 = 0 + 5t \\ \\ \sf \implies 44 = 5t \\ \\ \sf \implies 5t = 44 \\ \\ \sf \implies t = (44)/(5) \\ \\ \sf \implies t = 8.8 \: s`