Answer:
73, 74, 75
Explanation:
So the sum of three consecutive integers is 222.
Let's let the first integer be n.
Then the second integer must be (n+1).
And the third integer must be (n+2).
They total 222, thus:
![n+(n+1)+(n+2)=222](https://img.qammunity.org/2021/formulas/mathematics/high-school/lf0g6ysvc7rqd0pgx108idkyb6oifctnos.png)
Combine like terms:
![3n+3=222](https://img.qammunity.org/2021/formulas/mathematics/high-school/cr3fl5pyo1g75fawgcdnacuwkqbuj8phrb.png)
Subtract 3 from both sides:
![3n=219](https://img.qammunity.org/2021/formulas/mathematics/high-school/jztp7rg6z1zzzy92ej3rti7i3hakap0meb.png)
Divide both sides by 3:
![n=73](https://img.qammunity.org/2021/formulas/mathematics/high-school/vy5v589ovpr53t9tcf8qkuo0xs8yrxkes4.png)
So, the first integer is 73.
So our sequence is 73, 74, and 75.
And we're done!