Question

Kobe's bike wheel has a diameter of 2.75 feet. If he rides forward until the wheel makes 20 rotations, how far does he travel? (round to the nearest tenth)

Answer 1

Kobe traveled a distance of 172.80 ft

Explanation:

Given;

number of rotations of the bike, n = 20 rotations

diameter of the bike, d = 2.75 feet

radius of the bike, r = d/2 = 1.375 ft

Circumference of the bike wheel is given by;

D = 2πr

D = 2π(1.375 ft)

D = 8.641 ft

1 complete rotation = 8.641 ft

20 complete rotations = ?

= 20 x 8.641

= 172.82 ft

= 172.80 ft

Therefore, Kobe traveled a distance of 172.80 ft