Question

Find the smallest power of 10 that will exceed M. Let M = 118,526.65902.

Answer 1

The smallest power of 10 that will exceed
`M` is
`10^(6)`.

Explanation:

We can use the following approach to determine the smallest power of 10 that will exceed M. We can transform that number into scientific notation, which is of the form:

`x.y * 10^(n)`,
`\forall \,x,y\in \mathbb{N}`

Where:

`x` - Integer part, formed by a digit, which is of the highest order.

`y` - Decimal part, formed by a digit onwards.

`n` - Power grade.

The smallest power of 10 that will exceed M is
`10^(n+1)`

If
`M = 118,526.65902`, then, the power grade is number of spaces that dot must be moved leftwards. In this case, dot must be moved 5 spaces on the left. The integer part is 1 and the decimal part is 1852665902. Then, the value of
`M` in scientific notation is:

`M = 1.1852665902* 10^(5)`

Then, the smallest power of 10 that will exceed
`M` is
`10^(6)`.