Question

Ralph has a new rectangular back yard. The area of the back yard is 32 feet. The Length of the rectangle is 2 times the Width. Find the perimeter of the rectangular back yard.

Answer 1

24 feet

Explanation:

Let w represent the width of the rectangle. Then its length is 2w, and its area is ...

A = Lw

32 = (2w)(w) = 2w^2 . . . fill in the given values

16 = w^2 . . . . . . . . . . . . divide by 2

4 = w . . . . . . . . . . . . . . take the square root

8 = 2w = L . . . . . . . . . find the length

The dimensions of the yard are 8 feet long and 4 feet wide.

__

The perimeter is ...

P = 2(L +w) = 2(8 +4) = 2(12) = 24 . . . . feet

The perimeter of the rectangular back yard is 24 feet.