Question

A 2% suspension in saline contains how many ml per 5 ml saline?

Answer 1

There are 0.1 mililiters in 5 milimeters saline.

Explanation:

A 2 % suspension means that 2 % of the volume of a given substance per each 100 milimeters of saline. That is:

`r = (V_(sub))/(V_(sal))`

`V_(sub) = r\cdot V_(sal)`

Where:

`r` - Suspension ratio, dimensionless.

`V_(sal)` - Saline volume, measured in milimeters.

`V_(sub)` - Substance volume, measured in milimeters.

Given that
`r = 0.02` and
`V_(sal) = 5\,mL`, the volume of the substance is:

`V_(sub) = 0.02\cdot (5\,mL)`

`V_(sub) = 0.1\,mL`

There are 0.1 mililiters in 5 milimeters saline.