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Because of their connection with secant lines, tangentlines, and instantaneous rates, limits of the form

lim f(x + h) - f(x)h occur frequently in calculus. Evaluatet his limit for the given value of x and function f.
h→0

f(x)= 3√ x +5, x= 16

a. Does not exist
b. 24
c. 3/8
d.6

User GrAPPfruit
by
8.5k points

1 Answer

4 votes

Answer:

C. 3/8

Explanation:

Let
f' be defined as:


f'= \lim_(h \to 0) (f(x+h)-f(x))/(h)

Where:


f(x) = 3\cdot √(x)+5 and
f(x+h) =3\cdot √(x+h)+5

The definition is now expanded:


f' = \lim_(h \to 0) (3\cdot √(x+h)-3\cdot √(x))/(h)

By rationalization:


f' = 3\cdot \lim_(h \to 0) (( √(x+h)-√(x))\cdot (√(x+h)+√(x)))/(h\cdot (√(x+h)+√(x)))


f' = 3\cdot \lim_(h \to 0) (h)/(h\cdot (√(x+h)+√(x)))


f' = 3\cdot \lim_(h \to 0) (1)/(√(x+h)+√(x))


f' = 3\cdot \lim_(h \to 0) (1)/((x+h)^(1/2)+x^(1/2))

If
h = 0, then:


f' = (3)/(2\cdot x^(1/2))


f' = (3)/(2\cdot √(x))

Let evaluate
f'when
x = 16:


f'(16) = (3)/(2\cdot √(16))


f'(16) = (3)/(8)

Which corresponds to option C.

User Tanmay Mandal
by
8.4k points
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