Answer:
Option E. 12.04
Step-by-step explanation:
We begin by calculating the hydrogen ion concentration, [H+] in the solution. This can be obtained as follow:
HI will dissociate in solution as follow:
HI (aq) —> H+(aq) + I-(aq)
From the above equation,
1 mole of HI produced 1 mole of H+.
Therefore, 0.011 M HI solution will also produce 0.011 M H+ solution.
Therefore, the hydrogen ion concentration, [H+] in the solution is 0.011 M
Next, we shall determine the pH of the solution. This can be obtained as follow:
Hydrogen ion concentration, [H+] = 0.011 M
pH =?
pH = – Log [H+]
pH = – Log 0.011
pH = 1.96
Finally, we shall determine the pOH of the solution as follow:
pH = 1.96
pOH =?
pH + pOH = 14
1.96 + pOH = 14
Collect like terms
pOH = 14 – 1.96
pOH = 12.04
Therefore, the pOH of the solution is 12.04