Question

An airplane lands on the runway at a velocity of 22.7m/s. The plane accelerates at a rate of -3.3m/s2 until it comes to rest. How much time does it take the plane to stop? (round to the nearest tenth).

Answer 1

time = 6.9 s

Step-by-step explanation:

velocity of the plane v = 22.7 m/s

acceleration of the train a = -3.3 m/s^2

it finally comes to res, final velocity u = 0 m/s

time t = ?

using the equation

v = u + at

substituting, we have

0 = 22.7 + (-3.3)t

0 = 22.7 - 3.3t

3.3t = 22.7

t = 22.7/3.3 = 6.9 s