Answer:
A. Using
F= Eq
We substitute
= 2550NC x 1.6*10-19C
4.08*10^-16N
B.
Acceleration = F/m
So a = 4.08x10^ -16/1.67*10^-27
2.4*10^11m/s²
C.
Velocity= a x t
So V= 2.4x10^11 x 1.4*10-6
3.4*105m/s
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