Question

Janae drew point A located at (-2,5), and point located at (6, -1). What is the x-coordinate of point B that bisects AC? ​

Answer 1

The x coordinate is 2

Explanation:

Given

`A = (-2,5)`

`C = (6,-1)`

Required

Determine the x coordinate of B

Since B is the bisector of AC, then B is the midpoint and will be calculated using;

`B(x,y) = ((x_1 + x_2)/(2),(y_1 + y_2)/(2))`

Considering the x coordinates alone;

`x = (x_1 + x_2)/(2)`

Where

`(x_1,y_1) = (-2,5)` and
`(x_2,y_2) = (6,-1)`

Substitute values for x1 and x2

`x = (-2 + 6)/(2)`

`x = (4)/(2)`

`x = 2`

Hence;

The x coordinate is 2