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Given segment AB with points (-4, 8) and (6, 3) respectively. Find the coordinates of point P that partitions Segment AB in the ratio 3:2. The answer should be entered in the form (x,y) with out any spaces between characters.

User Nshaw
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1 Answer

6 votes

Answer:


P = (2,5)

Explanation:

Given


A(-4,8)


B(6,3)


m:n = 3 : 2

Required

Determine P

Since P divides the segment into 3:2, P is calculated using


P = ((nx_1 +m x_2)/(m+n),(ny_1 + my_2)/(m+n))

Where


(x_1,y_1) = (-4,8)


(x_2,y_2) = (6,3)


m:n = 3 : 2

Substitute these values in the above formula:


P = ((2 * -4 +3 * 6)/(3 + 2),(2 * 8 + 3 * 3)/(3 + 2))


P = ((-8 +18)/(3 + 2),(16 + 9)/(3 + 2))


P = ((10)/(5),(25)/(5))


P = (2,5)

User Gbaor
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