Answer:
(5.5,8) and (5.5,3) are the possible midpoints
Explanation:
Given
![D = 11](https://img.qammunity.org/2021/formulas/mathematics/high-school/covhlbb4v2020s9zvy7gx1jjysz4aym192.png)
![DE = 5](https://img.qammunity.org/2021/formulas/mathematics/high-school/98tn7tvyd384ei844blyp0eqir7319lyoh.png)
Required
Determine the midpoint of DE
First, we need to determine the coordinates of E
If E is at the right of DE, then
![D - E = 5](https://img.qammunity.org/2021/formulas/mathematics/high-school/7u9lm4z2qeumvpg1ejwxuk77lhvdhkpw03.png)
![11 - E = 5](https://img.qammunity.org/2021/formulas/mathematics/high-school/myigqnnx0i99esgrprqo3gobwqtbvuz2ed.png)
![E = 11 - 5](https://img.qammunity.org/2021/formulas/mathematics/high-school/9dgsltmkvmqpscuewxvqvc8w0jxbym4s1d.png)
![E = 6](https://img.qammunity.org/2021/formulas/mathematics/high-school/22zu9umzhmfb1gtegnrdzcqqm47n6z1n3k.png)
Hence,
(D,E) = (11,6)
Calculate Midpoint
![Midpoint = (1)/(2) * (11,6)](https://img.qammunity.org/2021/formulas/mathematics/high-school/1ajt1lnltqrc2wdftjkxulsy1uojo6e7xs.png)
![Midpoint = (5.5,3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/c9630pskccczkucjntqz7r8xmxkil6pgq5.png)
Else:
![E - D = 5](https://img.qammunity.org/2021/formulas/mathematics/high-school/noisvql3uq0nij1f6ouhw6nnma0wzxzf08.png)
![E - 11 = 5](https://img.qammunity.org/2021/formulas/mathematics/high-school/ofh1nl0cec0je4m3r9p0g8a69bbdt2xqhs.png)
![E = 11 + 5](https://img.qammunity.org/2021/formulas/mathematics/high-school/3yljbshqa8jj7ot2zld9lcvvwqj77g0g35.png)
![E = 16](https://img.qammunity.org/2021/formulas/mathematics/high-school/n5f57zvqeo2uu1q91wjs32ecafk9wlmjeu.png)
Hence,
(D,E) = (11,16)
Calculate Midpoint
![Midpoint = (1)/(2) * (11,16)](https://img.qammunity.org/2021/formulas/mathematics/high-school/nm6dm6tbok8vxpblrlrdyi1bvoqyxplmqp.png)
![Midpoint = (5.5,8)](https://img.qammunity.org/2021/formulas/mathematics/high-school/37ljb6nisydyf5k2wgzhe4y5puykbm13pv.png)
(5.5,8) and (5.5,3) are the possible midpoints