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How many moles of NaOH are present in 65.00 g of NaOH(s)? *

How many moles of NaOH are present in 65.00 g of NaOH(s)? *-example-1

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Answer:

The answer is option B

Step-by-step explanation:

To find the number of moles we must first find the molar mass of the compound after that we use the formula


n = (m)/(M)

where

n is the number of moles

M is the molar mass

m is the mass

M(Na) = 23 , M(O) = 16 , M(H) = 1

Molar mass ( NaOH ) = 23+ 16 + 1

= 40 g/mol

mass = 65 g

Substitute the values into the above formula and solve

That's


n = (65)/(40) = (13)/(8)

We have the final answer as

1.625 moles

Hope this helps you

User Kishon
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