Answer:
The numbers are
2730 and 2940
Explanation:
From the question we are finding any two given numbers that's closest to 3000 exactly divisible by 5 , 7 , 14 and 15
Which means that the numbers above can exactly divide those two numbers without a remainder.
The numbers closest to 3000 which have this property are
2730 and 2940
Proof
For 2730
2730 ÷ 5 = 546 no remainder
2730 ÷ 7 = 390 no remainder
2730 ÷ 14 = 195 no remainder
2730 ÷ 15 = 182 no remainder
For 2940
2940 ÷ 5 = 588 no remainder
2940 ÷ 7 = 420 no remainder
2940 ÷ 14 = 210 no remainder
2940 ÷ 15 = 196 no remainder
The above proof shows that the answers are true
Hope this helps you