Question

(-3,1) and (-1,-1)
The distance AB rounded to the nearest tenth =?

Answer 1

The answer is

2.8 units

Explanation:

The distance between two points can be found by using the formula

`d = \sqrt{( {x1 - x2})^(2) + ({y1 - y2})^(2) } \\`

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(-3,1) and (-1,-1)

The distance between them is

`|AB| = \sqrt{ ({ - 3 + 1})^(2) + ( {1 + 1})^(2) } \\ = \sqrt{( { - 2})^(2) + {2}^(2) } \\ = √(4 + 4) \\ = √(8) \: \: \\ = 2 √(2) \\ \: \: \: \: = 2.8284`

We have the final answer as

2.8 units to the nearest tenth

Hope this helps you