Question

​(4x2−2x+28​)+​(4x2+4x−55​)

Answer 1

`\boxed{ \bold{ \boxed{ \sf{8 {x}^(2) + 2x - 27}}}}`

Explanation:

`\sf{(4 {x}^(2) - 2x + 28) + (4 {x}^(2) + 4x - 55)}`

When there is a ( + ) in front of an parentheses in an expression, there is no need to change the sign of each term in the expression. That means , the expression remains the same. Just, remove the unnecessary parentheses

`\dashrightarrow{ \sf{4 {x}^(2) - 2x + 28 + 4 {x}^(2) + 4x - 55}}`

Collect like terms and simplify

`\dashrightarrow{ \sf{4 {x}^(2) + 4 {x}^(2) - 2x + 4x + 28 - 55}}`

`\dashrightarrow{ \sf{8 {x}^(2) + 2x + 28 - 55}}`

The negative and positive integers are always subtracted but possess the sign of the bigger integer.

`\dashrightarrow{ \sf{8 {x}^(2) + 2x - 27}}`

Hope I helped!

Best regards! :D