Question

A cylinder has a radius of 6 centimeters and a height of 18 centimeters. A smaller cylinder has linear dimensions that are one-third the dimensions of the larger cylinder. Compare the surface area of the smaller cylinder to the surface area of the larger cylinder.

Answer 1

the larger cyclinder has a surface area which is 9 times the surface area of the smaller cyclinder.

Explanation:

Surface area of larger cyclinder

Radius = 6cm

Height = 18cm

A = 2πrh + 2πr^2

= 2*3.14*6*18 + 2*3.14*6^2

= 678.24 + 226.08

= 904.32 cm

Smaller cyclinder (1/3 of the larger cyclinder)

Radius = 2cm

Height = 6cm

A = 2πrh + 2πr^2

= 2*3.14*2*6 + 2*3.14*2^2

= 75.36 + 25.12

= 100.48 cm

Comparing the surface area of the larger cyclinder and the smaller cyclinder

= 904.32 cm / 100.48 cm

= 9

This means, the larger cyclinder has a surface area which is 9 times the surface area of the smaller cyclinder.