Answer:
The probability that Minh will roll a 5 is 1/6
Explanation:
The number of events = Minh rolls 4 + Minh rolls 5 + Minh rolls 6 + Minh rolls 7 + Minh rolls 8 + Minh rolls 9 = 6 events
The number of required outcome = Minh rolls 5
The probability, P, of an event occurring is defined as follows;
![P= (Number \, of \ required \ outcomes)/(Number \, of \ possible\, outcomes)](https://img.qammunity.org/2021/formulas/mathematics/high-school/ybgntrkvmvzzaa9mjot3yhx88odudgeuxf.png)
Which gives for the probability, P₅, that when Minh roll the number cube one he will roll a 5, we have
The number of possible outcomes = The number of events = 6
The number of required outcome = 1
Therefore;
![P_5= (1)/(6)](https://img.qammunity.org/2021/formulas/mathematics/high-school/koq7g2q11wr5t9dsq2jahite1g1x8czjsp.png)
Therefore, the probability that Minh will roll a 5 = 1/6.