Question

Q4. A particle starting from rest, travels with a = 5 m/s2. What is the distance traveled in 10 sec?

Answer 1

250 m

Step-by-step explanation:

Given :

Initial velocity, u = 0

Acceleration, a = 5 m/s2

Time elapsed is t = 10 seconds

The distance traveled in 10 seconds by the particle when accelerating at 5 m/s2 is given by,

`$ x = ut+(1)/(2)at^2$`

Putting the values,

`$ x = 0* 10+(1)/(2)(5)(10)^2$`

`$ x =(1)/(2)(5)(100)$`

x = 250 m

The particle moved 250 m in 10 seconds