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The largest ship in Christopher Columbus' "fleet" was the Santa Maria, which displaced about 100 tons (1 ton = 2,000 pounds) of seawater when fully loaded. Assuming the average density of seawater surrounding the ship was 1.024 g mL-1, calculate the total volume of seawater (in m3) displaced by the ship's hull.

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3 votes

Answer:


V=97.7m^3

Step-by-step explanation:

Hello,

In this case, considering that the density is defined in terms of mass and volume as follows:


\rho =(m)/(V)

Due to the fact that 100 tons of water were displaced, whose value in grams is:


m=100tons*(1000kg)/(1ton) *(1000g)/(1kg)=1x10^8g

Thus the displaced volume in cubic meters was:


V=(m)/(\rho)=(1x10^8g)/(1.024g/mL) =97656250mL\\\\V=97656250mL*(1L)/(1000mL)*(1m^3)/(1000L)\\ \\V=97.7m^3

Regards.

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