Question

Question 3 and 4 please!

Answer 1

Question 3:

1. 
   `f(x)=((2)/(3))x^2+3x-2\\`⇒standard form
2. 
   `f(x)=3x^2-8x+5(3x-8)`⇒intercept form
3. 
   `f(x)=4(x-5)^2+20`⇒ vertex form
4. 
   `f(x)=-(3x-8)(3x+5)`⇒none of the above

Question 4:Explain in detail how to solve the following function by completing the square:

`x^2+8x-9=0`

1. move the term to left side (done)

`x^2+8x-9=0`

2. use the quadratic formula

`x=(-b+√(b^2-4ac) )/(2a)`

A=1

B=8

C=-9

`x=(-(8)+√((8)^2-4(1)(-9)) )/(2(1))`

x=1

now check your answer.

1^2+8(1)-9=0