Question

Multiply (6 − 7i)(3 − 6i).

Answer 1

-24 - 57i

Explanation:

i'm assuming that this is a question about imaginary numbers and that i²= -1

we can expand the binomial by using the FOIL method (see attached)

(6 − 7i)(3 − 6i)

= (6)(3) + (6)(-6i) + (-7i)(3) + (-7i)(-6i)

=18 - 36i - 21i + 42i² (recall that i²= -1)

= 18 - 57i + 42(-1)

= 18 - 57i - 42

= -24 - 57i