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You are driving along the New York State Thruway in a line of cars all travelling at a constant speed of 108.5 km/hr. The car in front of you applies its brakes for maximum acceleration. You then apply your brakes to achieve the same maximum acceleration after only a 1 s delay due to reaction time. What distance behind the car in front of you must you be to avoid a collision?

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Answer:

Car first should be 30.13 m behind the second car.

Step-by-step explanation:

Given that,

Constant speed = 108.5 Km/hr

Time = 1 sec

Let the distance covered by second car S and by first car S'

We need to calculate the distance covered by second car

Using equation of motion


S=ut-(1)/(2)at^2.....(I)

The distance covered by first car to avoid collision


S''=S'+S

Put the value into the formula


S'+S=ut+ut-(1)/(2)at^2...(II)

We need to calculate the distance covered by first car

Using equation (I) and (II)


S'=ut

Put the value into the formula


S'=108.5*(5)/(18)*1


S'=30.13\ m

Hence, Car first should be 30.13 m behind the second car.

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