Question

If a gannet hits the water at 32 m/s, what height did it dive from? Assume that the gannet was motionless before starting its dive.

Answer 1

The value is
`h =  52.2 \  m`

Step-by-step explanation:

From the question we are told that

The velocity at which he hit the water is
`v  =  32 \  m/s`

Generally from kinematic equation

`v^2 =  u^2  + 2gh`

Here the initial velocity u = 0 m/ given that the gannet started the jump from rest.

=>
`32^2  =  0^2  +  2*(9.8)h`

=>
`h =  52.2 \  m`