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A 9-volt battery is used to power two lightbulbs in a series circuit. The first light bulb has a

resistance of 3 ohms and the second has a resistance of 2 ohms.

What is the power output of the battery?

Please show work if possible!

1 Answer

10 votes

Step-by-step explanation:

Total Resistance: 3+2 = 5 ohms

V=9V

Power = V²/R

=9²/5

=81/5

=16.2 W

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