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Find the center and radius for each equation of a circle (X+2)^2+y^2=13
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8 votes
Find the center and radius for each equation of a circle (X+2)^2+y^2=13

User Sashang
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1 Answer

8 votes

Explanation:


(x + 2) {}^(2) + {y}^(2) = 13 \\ comparing \: the \: equation \: with \: \\ (x - h) {}^(2) + (y - k) {}^(2) = r {}^(2) \\ center(h \: k) = ( - 2 \:\:\: 0) \\ r = √(13)

User Fletch
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