Answer:
a.
![1.019 * 10^(-7) N](https://img.qammunity.org/2021/formulas/physics/college/1g1p5ct6cbhnrs08gs3ye4yja2nnx883yd.png)
b. Repulsive force
Step-by-step explanation:
The computation is shown below:
a. The magnitude of the force is
Given that
Charge = 7.52nc
Location = 1.65m
Point charge = 4.10nC
Based on the above information,
As we know that
![F= (kqQ)/(r^2) \\\\= (9*10^(9) * 7.52 * 10^(-9) * 4.1 * 10^(-9))/(1.652) \\\\= 1.019 * 10^(-7) N](https://img.qammunity.org/2021/formulas/physics/college/kyrp07fpjscsxwifhr4syt6zzsj3a04yq8.png)
b. Now as it can be seen that both contains the positive charges so this represents the repulsive force and the same is to be considered