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If and acid has a Ka dissociation constant of 1 x 10-9 what is the pKa of this acid?

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Answer:

pKa = 9

Step-by-step explanation:

In this case, we have to remember the meaning of "p". When we use "p" in any calculation we have to apply the minus ten based logarithm, so:


p~=~-Log

For example, when we use the "pH" value. We have to apply the minus ten based logarithm of the concentration of the hydronium ion:


pH~=~-Log[H^+]

So, if we have wanted to calculate the pKa value. We have to apply the minus ten based logarithm of the Ka value, so:


pKa~=~-Log~Ka

Now we can plug the value into the equation:


pKa~=~-Log~1x10^-^9


pKa~=~9

The pKa value is 9.

I hope it helps!