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Find the inverse of the function f(x)=4x^3-7​

User Rytis I
by
7.6k points

1 Answer

2 votes

Answer:

f^-1(x)=³√[(x+7)÷4]

Explanation:

f(x)=4x^3-7

y=4x^3-7

interchange 'y' with 'x'

x=4y^3-7

make y the subject

4y^3=x+7

divide by 4 both sides

y^3=(x+7)÷4

multiply by the cube root both sides

³√(y^3)=³√[(x+7)÷4]

y=³√[(x+7)÷4]

f^-1(x)=³√[(x+7)÷4]

User Marijn
by
9.0k points

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