Answer:
The difference in energy production in kilowatt hours of monthly energy produced between an average local wind speed of 15 miles per hour and an average local wind speed of 10 miles per hour is approximately 9 kWh
Explanation:
We note that the energy produced is given by the formula;
Energy = 1/2 × m × v²
From which we have the energy per unit mass = 1/2 × v²
The energy produced by the wind traveling at 15 miles per hour is given as follows;
15 mph = 6.705 m/s
The energy per unit mass produced in a month of 30 days is therefore;
1/2×6.705²×60×60×24×30 = 58264304.4 J/kg
We note that 1 Kilowatt hour = 3.6 × 10⁶ Joules
Therefore;
58264304.4 J = 58264304.4 J/(3.6 × 10⁶) kWh = 16.184529 kWh
The energy produced by the wind traveling at 10 miles per hour is given as follows;
10 mph = 4.47 m/s
The energy per unit mass produced in a month of 30 days is therefore;
1/2×4.47²×60×60×24×30 = 25,895,246.4 J/kg
We note that 1 Kilowatt hour = 3.6 × 10⁶ Joules
Therefore;
25,895,246.4 J = 25,895,246.4 J/(3.6 × 10⁶) kWh = 7.193124 kWh
The difference in energy production in kilowatt hours of monthly energy produced between an average local wind speed of 15 miles per hour and an average local wind speed of 10 miles per hour is therefore;
16.184529 kWh - 7.193124 kWh = 8.991405 kWh. ≈ 9 kWh