Question

If .680 g/L of a gas is dissolved in water at 5.00 atm of pressure, how much will dissolve (in g/L) at 8.00 atm of pressure.

Answer 1

Density and pressure are directly proportional

`\\ \rm\Rrightarrow \rho_1P_2=\rho_2P_1`
`\\ \rm\Rrightarrow 0.680(8)=5\rho_2`

`\\ \rm\Rrightarrow 5.44=5\rho_2`

`\\ \rm\Rrightarrow \rho_2=1.088g/\ell`

Answer 2

`1.088\ g/L`

Step-by-step explanation:

Step 1: Determine the amount dissolved

`Density_(\ 1)*Pressure_(\ 2)=Density_(\ 2)*Presure_(\ 1)`

`0.680\ g/L*8\ atm=Density_(\ 2)*5\ atm`

`(5.44\ g*atm/L)/(5\ atm)=(Density_(\ 2)\ *\ 5\ atm)/(5\ atm)`

`1.088\ g/L=Density_(\ 2)`

Answer:
`1.088\ g/L`