Question

Find the height or length of these natural wonders in km, m, and cm.A. A cave system with a mapped length of 354 miles.B. A waterfall that drops 1,235.2 ft.C. A 21320 ft tall mountain.

D. A canyon with a depth of 6630 ft.

Answer 1

Step-by-step explanation:

Some standard unit conversion are 1 mile = 1.609344 km, 1 ft.= 30.48 cm,

1 km= 1000 m or 1 m = 0.001 km and 1 m= 100 cm or 1 cm=0.01 m.

Now, use these values to convert the given lengths.

A. length of cave = 5 miles (given)

From standard value 1 mile = 1.609344 km

`\Rightarrow` 5 miles =
`*` 1.609344 km= 8.04672 km,

`\Rightarrow` 5 miles =8.04672
`*` 1000 m= 8046.72 m [ as 1 km = 1000 m]

`\Rightarrow` 5 miles = 8046.72
`*` 100 cm=804672 cm

B. Height of the waterfall = 1235 ft. (given)

1 ft.= 30.48 cm [ from standard value]

`\Rightarrow` 1235.2 ft.= 1235.2
`*` 30.48 cm=37648.896 cm,

`\Rightarrow` 1235.2 ft.=37648.896
`*` 0.01 m =376.48896 m [ as 1 cm = 0.01 m]

`\Rightarrow` 1235.2 ft.=376.48896
`*` 0.001 km =0.37648896 km [ as 1 m = 0.001 km]

C. Height of the mountain= 21320 ft. (given)

From standard value: 1 ft.= 30.48 cm

`\Rightarrow` 21320 ft.= 21320
`*` 30.48 cm=649833.6 cm,

`\Rightarrow` 21320 ft.=649833.6
`*` 0.01 m =6498.336 m [ as 1 cm = 0.01 m]

`\Rightarrow` 21320 ft.=6498.336
`*` 0.001 km =6.498336 km [ as 1 m = 0.001 km].

D. Depth of canyon =6630 ft.

From standard value: 1 ft.= 30.48 cm

`\Rightarrow` 6630 ft.= 6630
`*` 30.48 cm=202082.4 cm,

`\Rightarrow` 6630 ft.=202082.4
`*` 0.01 m =2020.824 m [ as 1 cm = 0.01 m]

`\Rightarrow` 6630 ft.=2020.824
`*` 0.001 km =2.020824 km [ as 1 m = 0.001 km].