Question

Consider a triangle with vertices at S(-2, -3), A(2, 3), and N(5, -4). Find the length of each side rounding your answer to the nearest tenth and then determine which is the shortest.

The length of side SA is: type your answer...
The length of side AN is: type your answer...
and the length of side NS is: type your answer...
Therefore the shortest side is: type your answer...
CLASS ENDS IN ONE HOUR HELP

Answer 1

We can use the distance formula to solve: √(x2-x1)²+(y2-y1)²

Side SA:

√(2-(-2))²+(3-(-3))²

√4² + 6²

√16 + 36

√52

≈ 7.21

Side AN:

√(5-2)²+(-4-3)²

√3² + -7²

√9 + 49

√58

≈ 7.62

Side NS:

√(-2-5)²+(-3-(-4))²

√-7² + 1²

√49 + 1

√50

≈ 7.07

Therefore, the shortest side is "NS"

Best of Luck!