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Please answer this with explanation. Please I really am struggling. I will mark you brainalist. Please solve it Please

Please answer this with explanation. Please I really am struggling. I will mark you-example-1
User Asara
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10 votes

Answer:

13, 11, 4, 16, 6, 22

Explanation:

Let the second digit be x and the last digit be y

Given:

  • Data set: 13, x, 4, 16, 6, y
  • Mean = 12
  • y = 2x or x = 2y

The mean of the data is the average. The average can be calculated by determining the sum of the terms and dividing it by the total digits.


\implies \text{Mean of data:} \ (13 + x + 4 + 16 + 6 + y)/(6) = 12

Let us substitute the value of y (2x) in the data.


\implies (13 + x + 4 + 16 + 6 + 2x)/(6) = 12

Now, add all the terms in the data and simplify.


\implies (39 + x +2x)/(6) = 12


\implies (39 + 3x)/(6) = 12

Distribute the denominators and simplify.


\implies (39)/(6) + (3x)/(6) = 12


\implies (13)/(2) + (x)/(2) = 12


\implies 6.5 + (x)/(2) = 12

Subtract 6.5 both sides and simplify.


\implies 6.5 + (x)/(2) - 6.5 = 12 - 6.5


\implies (x)/(2) = 5.5

Use cross multiplication and simplify.


\implies x= 5.5 * 2


\implies x= 11

To determine the value of "y", simply substitute the value of "x" into the expression that represents the value of "y".


\implies y = 2x


\implies y = 2(11)


\implies y = 22

When the x and y values are substituted in the data, we get;

  • 13, 11, 4, 16, 6, 22

Therefore, the data is 13, 11, 4, 16, 6, 22.

User Cwd
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