135k views
2 votes
Solve the compound inequality: 3x + 6 < 12 AND 6x + 24 < 12

User Cnanney
by
8.4k points

1 Answer

4 votes

Answer:


x < -2.

Explanation:

It is given that
3x + 6 < 12 and
6x + 24 < 12.

For
3x + 6 < 12,


3x < 12-6


3x < 6

Divide both sides by 2.


x < 2 ...(i)

For
6x + 24 < 12,


6x< 12-24


6x< -12

Divide both sides by 6.


x < -2 ...(ii)

From (i) and (ii), we get


x < 2\text{ and }x<-2


\Rightarrow x<-2

Therefore, the required answer is
x < -2.

User ATD
by
8.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories