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Solve the compound inequality: 3x + 6 < 12 AND 6x + 24 < 12

User Cnanney
by
5.5k points

1 Answer

4 votes

Answer:


x < -2.

Explanation:

It is given that
3x + 6 < 12 and
6x + 24 < 12.

For
3x + 6 < 12,


3x < 12-6


3x < 6

Divide both sides by 2.


x < 2 ...(i)

For
6x + 24 < 12,


6x< 12-24


6x< -12

Divide both sides by 6.


x < -2 ...(ii)

From (i) and (ii), we get


x < 2\text{ and }x<-2


\Rightarrow x<-2

Therefore, the required answer is
x < -2.

User ATD
by
5.8k points