Answer :
- The complete balanced equation will be,
![Al(OH)_3(aq)+K_3PO_3(aq)\rightarrow AlPO_3(s)+3KOH(aq)](https://img.qammunity.org/2021/formulas/chemistry/high-school/dh51e6261w53hpjm7ki3e6zm7fz4e8up33.png)
- The complete ionic equation in separated aqueous solution will be,
![Al^(3+)(aq)+3OH^(-)(aq)+3K^(+)(aq)+PO_3^(3-)(aq)\rightarrow AlPO_3(s)+2K^+(aq)+3OH^(-)(aq)](https://img.qammunity.org/2021/formulas/chemistry/high-school/h9ncg4cxi69whser7hk9lls50q2wqecors.png)
- The net ionic equation will be,
![Al^(3+)(aq)+PO_3^(3-)(aq)\rightarrow AlPO_3(s)](https://img.qammunity.org/2021/formulas/chemistry/high-school/4yc05zoqha5u5y5px24ppkqs25xq6qitlk.png)
Explanation :
In the net ionic equations, we are not include the spectator ions in the equations.
Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.
The complete balanced equation will be,
![Al(OH)_3(aq)+K_3PO_3(aq)\rightarrow AlPO_3(s)+3KOH(aq)](https://img.qammunity.org/2021/formulas/chemistry/high-school/dh51e6261w53hpjm7ki3e6zm7fz4e8up33.png)
The complete ionic equation in separated aqueous solution will be,
![Al^(3+)(aq)+3OH^(-)(aq)+3K^(+)(aq)+PO_3^(3-)(aq)\rightarrow AlPO_3(s)+2K^+(aq)+3OH^(-)(aq)](https://img.qammunity.org/2021/formulas/chemistry/high-school/h9ncg4cxi69whser7hk9lls50q2wqecors.png)
In this equation,
are the spectator ions.
By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.
The net ionic equation will be,
![Al^(3+)(aq)+PO_3^(3-)(aq)\rightarrow AlPO_3(s)](https://img.qammunity.org/2021/formulas/chemistry/high-school/4yc05zoqha5u5y5px24ppkqs25xq6qitlk.png)