Answer:
C
Explanation:
To do this, let's let the decimal equal n. Thus:
![2.\bar1=n](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ghz8i4ple5rhs5ip6u5qyh21ziprytxwne.png)
There is only one digit repeating, so let's multiply both sides of the equation by 10:
![21.\bar1=10n](https://img.qammunity.org/2021/formulas/mathematics/middle-school/8m66w9oz5p7v8hre40vg2y9vz16t3jbvhb.png)
Now, subtract n from both sides:
![21.\bar1-n=10n-n](https://img.qammunity.org/2021/formulas/mathematics/middle-school/5s4i2z5h36l1hu6elolgpohovr9g0lsqx3.png)
On the right, it becomes 9n. However, the left, however, expand, the decimal. In other words:
![21.1111...-2.1111...=9n](https://img.qammunity.org/2021/formulas/mathematics/middle-school/s7a3rlvvlnzpzrdcsqwakf3fk0nc424q7g.png)
All of the repeating 1s will cancel out. Thus:
![21-2=9n](https://img.qammunity.org/2021/formulas/mathematics/middle-school/4l98m64oed6qma9l0lvdcr8j1pydc9q75f.png)
Subtract:
![19=9n](https://img.qammunity.org/2021/formulas/mathematics/middle-school/4q29zj00vkv2zg3wbvzxc2cbumionsrs71.png)
Divide both sides by 9:
![n=(19)/(9)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ep7ren9arup9gx2mv06ixqwgmzh0ggh5p9.png)
And since we set the decimal equal to n originally...
![2.\bar1=(19)/(9)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/nw6vzs6oihjxhnjdtvig2htnf8fmakkrcl.png)
And we're done!
Notes:
This is the algebraic way to write a repeating decimal into a fraction. You can, of course, always just use a calculator and guess and check.