91.2k views
5 votes
Please help. Need help

Please help. Need help-example-1
User Tehwalrus
by
4.0k points

2 Answers

0 votes

It's A. 21/10

What I did to get this. Is i wrote down 2.1 as a fraction: 2.1/1 then multiplied 10 to both the numerator and the denominator. (2.1 x 10)/(1 x 10)=21/10.

I hope this helps. I'm not sure if the "repeating" matters that much to the point of a different answer...

5 votes

Answer:

C

Explanation:

To do this, let's let the decimal equal n. Thus:


2.\bar1=n

There is only one digit repeating, so let's multiply both sides of the equation by 10:


21.\bar1=10n

Now, subtract n from both sides:


21.\bar1-n=10n-n

On the right, it becomes 9n. However, the left, however, expand, the decimal. In other words:


21.1111...-2.1111...=9n

All of the repeating 1s will cancel out. Thus:


21-2=9n

Subtract:


19=9n

Divide both sides by 9:


n=(19)/(9)

And since we set the decimal equal to n originally...


2.\bar1=(19)/(9)

And we're done!

Notes:

This is the algebraic way to write a repeating decimal into a fraction. You can, of course, always just use a calculator and guess and check.

User RichardW
by
5.1k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.