91.2k views
5 votes
Please help. Need help

Please help. Need help-example-1
User Tehwalrus
by
7.0k points

2 Answers

0 votes

It's A. 21/10

What I did to get this. Is i wrote down 2.1 as a fraction: 2.1/1 then multiplied 10 to both the numerator and the denominator. (2.1 x 10)/(1 x 10)=21/10.

I hope this helps. I'm not sure if the "repeating" matters that much to the point of a different answer...

5 votes

Answer:

C

Explanation:

To do this, let's let the decimal equal n. Thus:


2.\bar1=n

There is only one digit repeating, so let's multiply both sides of the equation by 10:


21.\bar1=10n

Now, subtract n from both sides:


21.\bar1-n=10n-n

On the right, it becomes 9n. However, the left, however, expand, the decimal. In other words:


21.1111...-2.1111...=9n

All of the repeating 1s will cancel out. Thus:


21-2=9n

Subtract:


19=9n

Divide both sides by 9:


n=(19)/(9)

And since we set the decimal equal to n originally...


2.\bar1=(19)/(9)

And we're done!

Notes:

This is the algebraic way to write a repeating decimal into a fraction. You can, of course, always just use a calculator and guess and check.

User RichardW
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.