Question

If a train (travelling from Albuquerque to Atlanta) is moving 33.9 meters per second when it accelerates at -2.02 m/s^2 for 1.01 seconds, what is the final velocity

Answer 1

The final velocity is 31.86 m/s.

Step-by-step explanation:

The final velocity can be found using the following equation:

`V_(f) = V_(0) + at`

Where:

`V_(f)` is the final velocity =?

`V_(0)` is the initial velocity = 33.9 m/s

a is the acceleration = -2.02 m/s²

t is the time = 1.01 s

`V_(f) = V_(0) + at = 33.9 m/s + (-2.02 m/s^(2))*1.01 s = 31.86 m/s`

Therefore, the final velocity is 31.86 m/s.

I hope it helps you!