Answer:
![\rho =8.50g/cm^3](https://img.qammunity.org/2021/formulas/chemistry/college/hj6n99w415h5bxmdc1domraxvk2vlsju9k.png)
Step-by-step explanation:
Hello,
In this case, due to the volume difference caused by the addition of the metal, one could notice that the volume of the metal is:
![V_(metal)=9.84cm^3-6.85cm^3=2.99cm^3](https://img.qammunity.org/2021/formulas/chemistry/college/b6u99kytef9x6bh30odlrnmv6r0grq2qoa.png)
In such a way, given the mathematical definition of density, it turns out:
![\rho =(m)/(V)=(25.4253g)/(2.99cm^3)\\\\\rho =8.50g/cm^3](https://img.qammunity.org/2021/formulas/chemistry/college/eib0cwrc7dau0skljo2waqu4w1c0jpmkif.png)
Regards.