Question

C is the midpoint of segment AB. Find the value of m+k.

A(-3,m)

B (4, -1)

C (k, 2)

Answer 1

The value of m + k =
`5+(1)/(2)` =
`(11)/(2)`.

Explanation:

We are given that C is the midpoint of segment AB where A(-3,m) , B (4, -1) , and C (k, 2).

As we know that the mid-point formula states that;

Mid-point =
`(a+b)/(2)`

This means that;

Mid-point of AB =
`(A+B)/(2)`

C(k, 2) =
`((-3+4)/(2), (m+(-1))/(2) )`

C(k, 2) =
`((1)/(2), (m-1)/(2) )`

This means that;

`k = (1)/(2)` and
`2=(m-1)/(2)`

`k = (1)/(2)` and
`m-1=4`

`k = (1)/(2)` and
`m = 4+1 = 5`

So, the value of m + k =
`5+(1)/(2)` =
`(11)/(2)`.