Question

Yvette drops her cell phone as she is getting out of the truck one day she noticed that the cell phone fell 1.5m to the ground how fast was the phone moving right before hitting the ground

Answer 1

The speed was 5.42 m/s

Step-by-step explanation:

The height of fall of the phone s = 1.5 m

The phone was at rest in her hand, so the initial velocity u = 0 m/s

The velocity right before the phone strikes the ground v = ?

Using the equation

`v^(2)` =
`u^(2)` + 2gs

where

g is the acceleration due to gravity = 9.81 m/s^2

substituting values, we have

`v^(2)` =
`0^(2)` + 2(9.81 x 1.5)

`v^(2)` = 29.43

v =
`√(29.43)` = 5.42 m/s