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Tim's bean sprout grew 3/ inches. Teegan's bean sprout grew 2 3/4 inches. How many more inches did Tim's bean sprout grow than Teegan's? First, estimate the difference mentally and explain your reasoning. Then find the actual difference.

User Linan
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1 Answer

3 votes

Answer:

Tim's bean sprout grow by more than
(5)/(8) \text{ inches}.

Explanation:

We are given that Tim's bean sprout grew 3 3/8 inches. Teegan's bean sprout grew 2 3/4 inches.

We have to find how many more inches did Tim's bean sprout grow than Teegan's.

Firstly, converting both the mixed fractions in improper fraction get;

Tim's bean sprout grew =
3(3)/(8) =
(27)/(8) \text{ inches}

Teegan's bean sprout grew =
2(3)/(4) =
(11)/(4) \text{ inches}

Since the denominator of both the fractions is not the same, so we can't compare them both as which is larger or smaller.

Tim's bean sprout grew =
(27* 1)/(8* 1) = (27)/(8) \text{ inches}

Teegan's bean sprout grew =
(11 * 2)/(4* 2)=(22)/(8) \text{ inches}

Now, we can clearly see that Tim's bean sprout grew more than Teegan's bean sprout.

So, Tim's bean sprout grow by more than =
(27)/(8)- (22)/(8) =
(5)/(8) \text{ inches}

Hence, Tim's bean sprout grow by more than
(5)/(8) \text{ inches}.

User Andrewsi
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