Question

Find the x and y intercepts of the circle: (x-6)^2+(y+3)^2=16

Answer 1

-y+11

Explanation:

(x-6)•2+(y+3)•2-(y+3)•2=16-(y+3)•2

(x-6)•2=-2y+10

(x-6)•=-2y/2+10/2

x-6=-y+5

x=-y+11

Answer 2

Answer: x=0 y=2

Explanation: