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5 votes
The bells are adding a new room to their house. The room will be a cube with volume of 4,913 feet cubed. They are going to put in hardwood floors, and the contractor charged $5 per square foot. How much will the j hardwood floors cost?

User Menghan
by
5.4k points

1 Answer

5 votes

Answer:

$1445

Explanation:

The side length of the room is the cube root of the volume of the cube:

s = ∛4913 = 17 . . . . feet

The area of the floor is the square of this side length:

A = (17 ft)² = 289 ft²

The cost of the floor is $5 for each square foot:

cost = ($5/ft²)(289 ft²) = $1445

The hardwood floor will cost $1445.

User Axk
by
5.4k points
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